Integral of nx^(n-1) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫nxn−1dx=n∫xn−1dx
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The integral of xn is n+1xn+1 when n=−1:
∫xn−1dx={nxnlog(x)forn−1=−1otherwise
So, the result is: n({nxnlog(x)forn−1=−1otherwise)
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Now simplify:
{xnnlog(x)forn=0otherwise
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Add the constant of integration:
{xnnlog(x)forn=0otherwise+constant
The answer is:
{xnnlog(x)forn=0otherwise+constant
The answer (Indefinite)
[src]
/ // n \
| || x |
| n - 1 || -- for n - 1 != -1|
| n*x dx = C + n*|< n |
| || |
/ ||log(x) otherwise |
\\ /
∫nxn−1dx=C+n({nxnlog(x)forn−1=−1otherwise)
/ n
| 1 - 0 for And(n > -oo, n < oo, n != 0)
<
|oo*sign(n) otherwise
\
{1−0n∞sign(n)forn>−∞∧n<∞∧n=0otherwise
=
/ n
| 1 - 0 for And(n > -oo, n < oo, n != 0)
<
|oo*sign(n) otherwise
\
{1−0n∞sign(n)forn>−∞∧n<∞∧n=0otherwise
Piecewise((1 - 0^n, (n > -oo)∧(n < oo)∧(Ne(n, 0))), (oo*sign(n), True))
Use the examples entering the upper and lower limits of integration.