-2 + x
/
|
| 9
| -- dx
| 2
| x
|
/
2
Integral(9/x^2, (x, 2, -2 + x))
The integral of a constant times a function is the constant times the integral of the function:
PiecewiseRule(subfunctions=[(ArctanRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False), (ArccothRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False), (ArctanhRule(a=1, b=1, c=0, context=1/(x**2), symbol=x), False)], context=1/(x**2), symbol=x)
So, the result is:
Add the constant of integration:
The answer is:
/ | | 9 | -- dx = nan | 2 | x | /
9 9 - - ------ 2 -2 + x
=
9 9 - - ------ 2 -2 + x
9/2 - 9/(-2 + x)
Use the examples entering the upper and lower limits of integration.