Integral of ln^2x/1+x^2 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫1log(x)2dx=∫log(x)2dx
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Don't know the steps in finding this integral.
But the integral is
xlog(x)2−2xlog(x)+2x
So, the result is: xlog(x)2−2xlog(x)+2x
The result is: 3x3+xlog(x)2−2xlog(x)+2x
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Now simplify:
3x(x2+3log(x)2−6log(x)+6)
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Add the constant of integration:
3x(x2+3log(x)2−6log(x)+6)+constant
The answer is:
3x(x2+3log(x)2−6log(x)+6)+constant
The answer (Indefinite)
[src]
/
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| / 2 \ 3
| |log (x) 2| x 2
| |------- + x | dx = C + 2*x + -- + x*log (x) - 2*x*log(x)
| \ 1 / 3
|
/
x((logx)2−2logx+2)+3x3
Use the examples entering the upper and lower limits of integration.