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- Improper integral
- Double Integral
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How to use it?
- Integral of d{x}:
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Integral of cos^2x
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Integral of (cos(x))^2
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Integral of 8x
- Integral of sqrt(1+cosx)
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Identical expressions
- secx/(secx+tanx)
- secx divide by (secx plus tangent of x)
- secx/secx+tanx
- secx divide by (secx+tanx)
- secx/(secx+tanx)dx
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Similar expressions
- secx/(secx-tanx)
Integral of secx/(secx+tanx) dx
The solution
You have entered
[src]
1 / | | sec(x) | --------------- dx | sec(x) + tan(x) | / 0
$$\int\limits_{0}^{1} \frac{\sec{\left(x \right)}}{\tan{\left(x \right)} + \sec{\left(x \right)}}\, dx$$
Integral(sec(x)/(sec(x) + tan(x)), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | sec(x) | sec(x) | --------------- dx = C + | --------------- dx | sec(x) + tan(x) | sec(x) + tan(x) | | / /
$$-{{2}\over{{{\sin x}\over{\cos x+1}}+1}}$$
The answer
[src]
1 / | | sec(x) | --------------- dx | sec(x) + tan(x) | / 0
$$-{{2\,\cos 1}\over{\sin 1+\cos 1+1}}-{{2}\over{\sin 1+\cos 1+1}}+2$$
=
=
1 / | | sec(x) | --------------- dx | sec(x) + tan(x) | / 0
$$\int\limits_{0}^{1} \frac{\sec{\left(x \right)}}{\tan{\left(x \right)} + \sec{\left(x \right)}}\, dx$$
Use the examples entering the upper and lower limits of integration.