Integral of exp(-x/2) dx
The solution
Detail solution
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Let u=2(−1)x.
Then let du=−2dx and substitute −2du:
∫(−2eu)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: −2eu
Now substitute u back in:
−2e2(−1)x
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Now simplify:
−2e−2x
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Add the constant of integration:
−2e−2x+constant
The answer is:
−2e−2x+constant
The answer (Indefinite)
[src]
/
|
| -x -x
| --- ---
| 2 2
| e dx = C - 2*e
|
/
∫e2(−1)xdx=C−2e2(−1)x
The graph
2−e232
=
2−e232
Use the examples entering the upper and lower limits of integration.