Integral of e^(x^2)*x^3 dx
The solution
Detail solution
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Let u=x2.
Then let du=2xdx and substitute 2du:
∫2ueudu
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The integral of a constant times a function is the constant times the integral of the function:
∫ueudu=2∫ueudu
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Use integration by parts:
∫udv=uv−∫vdu
Let u(u)=u and let dv(u)=eu.
Then du(u)=1.
To find v(u):
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The integral of the exponential function is itself.
∫eudu=eu
Now evaluate the sub-integral.
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: 2ueu−2eu
Now substitute u back in:
2x2ex2−2ex2
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Now simplify:
2(x2−1)ex2
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Add the constant of integration:
2(x2−1)ex2+constant
The answer is:
2(x2−1)ex2+constant
The answer (Indefinite)
[src]
/
| / 2\ / 2\
| / 2\ \x / 2 \x /
| \x / 3 e x *e
| E *x dx = C - ----- + --------
| 2 2
/
∫ex2x3dx=C+2x2ex2−2ex2
The graph
Use the examples entering the upper and lower limits of integration.