Integral of cos(3x-2) dx

The solution

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 |  cos(3*x - 2) dx
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$$\int\limits_{0}^{0} \cos{\left(3 x - 2 \right)}\, dx$$

Integral(cos(3*x - 1*2), (x, 0, 0))

Detail solution

Let $u = 3 x - 2$ .

Then let $du = 3 dx$ and substitute $\frac{du}{3}$ :

$\int \frac{\cos{\left(u \right)}}{9}\, du$
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int \frac{\cos{\left(u \right)}}{3}\, du = \frac{\int \cos{\left(u \right)}\, du}{3}$
  1. The integral of cosine is sine:
    
    $\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}$
  So, the result is: $\frac{\sin{\left(u \right)}}{3}$
Now substitute $u$ back in:

$\frac{\sin{\left(3 x - 2 \right)}}{3}$
Now simplify:

$\frac{\sin{\left(3 x - 2 \right)}}{3}$
Add the constant of integration:

$\frac{\sin{\left(3 x - 2 \right)}}{3}+ \mathrm{constant}$

The answer is:

$\frac{\sin{\left(3 x - 2 \right)}}{3}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                  
 |                       sin(3*x - 2)
 | cos(3*x - 2) dx = C + ------------
 |                            3      
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$${{\sin \left(3\,x-2\right)}\over{3}}$$

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The answer [src]

$$0$$

Simplify

Numerical answer [src]

0.0

0.0

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Use the examples entering the upper and lower limits of integration.

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Integral of cos(3x-2) dx

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