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Solving integrals/ (6x+3)/((x+1)(x-4))

Integral of (6x+3)/((x+1)(x-4)) dx

Limits of integration:

from to
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The graph:

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Piecewise:

The solution

You have entered [src] 
  1                   
  /                   
 |                    
 |      6*x + 3       
 |  --------------- dx
 |  (x + 1)*(x - 4)   
 |                    
/                     
0
∫016x+3(x−4)(x+1) dx\int\limits_{0}^{1} \frac{6 x + 3}{\left(x - 4\right) \left(x + 1\right)}\, dx 
Integral((6*x + 3)/(((x + 1)*(x - 4))), (x, 0, 1))
The answer (Indefinite) [src] 
  /                                                      
 |                                                       
 |     6*x + 3              3*log(1 + x)   27*log(-4 + x)
 | --------------- dx = C + ------------ + --------------
 | (x + 1)*(x - 4)               5               5       
 |                                                       
/
∫6x+3(x−4)(x+1) dx=C+27log⁡(x−4)5+3log⁡(x+1)5\int \frac{6 x + 3}{\left(x - 4\right) \left(x + 1\right)}\, dx = C + \frac{27 \log{\left(x - 4 \right)}}{5} + \frac{3 \log{\left(x + 1 \right)}}{5}
Simplify
The graph
0.001.000.100.200.300.400.500.600.700.800.90-2.00.0
Plot the graph f(x)
The answer [src] 
  27*log(4)   3*log(2)   27*log(3)
- --------- + -------- + ---------
      5          5           5
−27log⁡(4)5+3log⁡(2)5+27log⁡(3)5- \frac{27 \log{\left(4 \right)}}{5} + \frac{3 \log{\left(2 \right)}}{5} + \frac{27 \log{\left(3 \right)}}{5} 
=
= 
  27*log(4)   3*log(2)   27*log(3)
- --------- + -------- + ---------
      5          5           5
−27log⁡(4)5+3log⁡(2)5+27log⁡(3)5- \frac{27 \log{\left(4 \right)}}{5} + \frac{3 \log{\left(2 \right)}}{5} + \frac{27 \log{\left(3 \right)}}{5} 
-27*log(4)/5 + 3*log(2)/5 + 27*log(3)/5
Numerical answer [src] 
-1.13759488290365
-1.13759488290365

    Use the examples entering the upper and lower limits of integration.

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