Integral of (4x^3-6x^2-4x+3)dx dx

1. Integrate term-by-term:

   1. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int \left(- 4 x\right)\, dx = - 4 \int x\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x\, dx = \frac{x^{2}}{2}$$

         So, the result is: $- 2 x^{2}$

      1. Integrate term-by-term:

         1. The integral of a constant times a function is the constant times the integral of the function:

            $$\int 4 x^{3}\, dx = 4 \int x^{3}\, dx$$

            1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

               $$\int x^{3}\, dx = \frac{x^{4}}{4}$$

            So, the result is: $x^{4}$

         1. The integral of a constant times a function is the constant times the integral of the function:

            $$\int \left(- 6 x^{2}\right)\, dx = - 6 \int x^{2}\, dx$$

            1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

               $$\int x^{2}\, dx = \frac{x^{3}}{3}$$

            So, the result is: $- 2 x^{3}$

         The result is: $x^{4} - 2 x^{3}$

      The result is: $x^{4} - 2 x^{3} - 2 x^{2}$

   1. The integral of a constant is the constant times the variable of integration:

      $$\int 3\, dx = 3 x$$

   The result is: $x^{4} - 2 x^{3} - 2 x^{2} + 3 x$

2. Now simplify:

   $$x \left(x^{3} - 2 x^{2} - 2 x + 3\right)$$

3. Add the constant of integration:

   $$x \left(x^{3} - 2 x^{2} - 2 x + 3\right)+ \mathrm{constant}$$

The answer is:

$$x \left(x^{3} - 2 x^{2} - 2 x + 3\right)+ \mathrm{constant}$$