Integral of 3y^2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫3y2dy=3∫y2dy
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The integral of yn is n+1yn+1 when n=−1:
∫y2dy=3y3
So, the result is: y3
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Add the constant of integration:
y3+constant
The answer is:
y3+constant
The answer (Indefinite)
[src]
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| 2 3
| 3*y dy = C + y
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The graph
Use the examples entering the upper and lower limits of integration.