Integral of (3sinx-e^x+2)dx dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−ex)dx=−∫exdx
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The integral of the exponential function is itself.
∫exdx=ex
So, the result is: −ex
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The integral of a constant times a function is the constant times the integral of the function:
∫3sin(x)dx=3∫sin(x)dx
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The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
So, the result is: −3cos(x)
The result is: −ex−3cos(x)
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The integral of a constant is the constant times the variable of integration:
∫2dx=2x
The result is: 2x−ex−3cos(x)
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Add the constant of integration:
2x−ex−3cos(x)+constant
The answer is:
2x−ex−3cos(x)+constant
The answer (Indefinite)
[src]
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| / x \ x
| \3*sin(x) - E + 2/ dx = C - e - 3*cos(x) + 2*x
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∫((−ex+3sin(x))+2)dx=C+2x−ex−3cos(x)
The graph
−e−3cos(1)+6
=
−e−3cos(1)+6
Use the examples entering the upper and lower limits of integration.