Given the inequality: x2+2x−5<0 To solve this inequality, we must first solve the corresponding equation: x2+2x−5=0 Solve: This equation is of the form ax2+bx+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=1 b=2 c=−5 , then D=b2−4ac= 22−1⋅4(−5)=24 Because D > 0, then the equation has two roots. x1=2a(−b+D) x2=2a(−b−D) or x1=−1+6 Simplify x2=−6−1 Simplify x1=−1+6 x2=−6−1 x1=−1+6 x2=−6−1 This roots x2=−6−1 x1=−1+6 is the points with change the sign of the inequality expression. First define with the sign to the leftmost point: x0<x2 For example, let's take the point x0=x2−101 = (−6−1)−101 = −6−1011 substitute to the expression x2+2x−5<0 2(−6−1011)−5+(−6−1011)2<0