+x+12>5 inequation

Given the inequality:
$$x + 12 > 5$$
To solve this inequality, we must first solve the corresponding equation:
$$x + 12 = 5$$
Solve:
Given the linear equation:

+x+12 = 5

Move free summands (without x)
from left part to right part, we given:
$$x = -7$$
$$x_{1} = -7$$
$$x_{1} = -7$$
This roots
$$x_{1} = -7$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-7 + - \frac{1}{10}$$
=
$$- \frac{71}{10}$$
substitute to the expression
$$x + 12 > 5$$
$$- \frac{71}{10} + 12 > 5$$

49    
-- > 5
10    

Then
$$x < -7$$
no execute
the solution of our inequality is:
$$x > -7$$

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