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Inequation
:
x^2>-x-2
(1/2)*x-4*(x-3)>3*x
log((4-x)/(2x+1))<=log((4-x)/8)+log((4-x)/(x^2))
2x²-3x+10<0
Graphing y =
:
x^2
-x-2
Derivative of
:
x^2
Integral of d{x}
:
x^2
-x-2
Identical expressions
x^ two >-x- two
x squared greater than minus x minus 2
x to the power of two greater than minus x minus two
x2>-x-2
x²>-x-2
x to the power of 2>-x-2
Similar expressions
x^2>-x+2
sinx^2<1/4
sqrt(x^2-x-1)>sqrt(x+7)
4x^2-9>=0
x^2>+x-2
x^4-2x^2+1/2x^2-7x+6<=x^4-2x^2+1/2x^2-x-6
(50*9^x-100+50*9^(-x))/(9^x+2+9^(-x))-(20*20*9^x)/(9^x+1)<=(5*9^(x+0.5)-15)/(9^x)+1
(2^(5+x)-2^(-x))/(2^(3-x)-2^(-2x))>=2^x
Solving inequalities
/
x^2>-x-2
x^2>-x-2 inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
2 x > -x - 2
$$x^{2} > - x - 2$$
x^2 > -x - 2
Solving inequality on a graph
Rapid solution
[src]
And(-oo < x, x < oo)
$$-\infty < x \wedge x < \infty$$
(-oo < x)∧(x < oo)
Rapid solution 2
[src]
(-oo, oo)
$$x\ in\ \left(-\infty, \infty\right)$$
x in Interval(-oo, oo)