sinx^2<1/4 inequation

Given the inequality:
$$\sin^{2}{\left(x \right)} < \frac{1}{4}$$
To solve this inequality, we must first solve the corresponding equation:
$$\sin^{2}{\left(x \right)} = \frac{1}{4}$$
Solve:
Given the equation
$$\sin^{2}{\left(x \right)} = \frac{1}{4}$$
transform
$$\sin^{2}{\left(x \right)} - \frac{1}{4} = 0$$
$$\sin^{2}{\left(x \right)} - \frac{1}{4} = 0$$
Do replacement
$$w = \sin{\left(x \right)}$$
This equation is of the form

a*w^2 + b*w + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$w_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$w_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = - \frac{1}{4}$$
, then

D = b^2 - 4 * a * c = 

(0)^2 - 4 * (1) * (-1/4) = 1

Because D > 0, then the equation has two roots.

w1 = (-b + sqrt(D)) / (2*a)

w2 = (-b - sqrt(D)) / (2*a)

or
$$w_{1} = \frac{1}{2}$$
Simplify
$$w_{2} = - \frac{1}{2}$$
Simplify
do backward replacement
$$\sin{\left(x \right)} = w$$
Given the equation
$$\sin{\left(x \right)} = w$$
- this is the simplest trigonometric equation
This equation is transformed to
$$x = 2 \pi n + \operatorname{asin}{\left(w \right)}$$
$$x = 2 \pi n - \operatorname{asin}{\left(w \right)} + \pi$$
Or
$$x = 2 \pi n + \operatorname{asin}{\left(w \right)}$$
$$x = 2 \pi n - \operatorname{asin}{\left(w \right)} + \pi$$
, where n - is a integer
substitute w:
$$x_{1} = 2 \pi n + \operatorname{asin}{\left(w_{1} \right)}$$
$$x_{1} = 2 \pi n + \operatorname{asin}{\left(\frac{1}{2} \right)}$$
$$x_{1} = 2 \pi n + \frac{\pi}{6}$$
$$x_{2} = 2 \pi n + \operatorname{asin}{\left(w_{2} \right)}$$
$$x_{2} = 2 \pi n + \operatorname{asin}{\left(- \frac{1}{2} \right)}$$
$$x_{2} = 2 \pi n - \frac{\pi}{6}$$
$$x_{3} = 2 \pi n - \operatorname{asin}{\left(w_{1} \right)} + \pi$$
$$x_{3} = 2 \pi n - \operatorname{asin}{\left(\frac{1}{2} \right)} + \pi$$
$$x_{3} = 2 \pi n + \frac{5 \pi}{6}$$
$$x_{4} = 2 \pi n - \operatorname{asin}{\left(w_{2} \right)} + \pi$$
$$x_{4} = 2 \pi n - \operatorname{asin}{\left(- \frac{1}{2} \right)} + \pi$$
$$x_{4} = 2 \pi n + \frac{7 \pi}{6}$$
$$x_{1} = - \frac{\pi}{6}$$
$$x_{2} = \frac{\pi}{6}$$
$$x_{3} = \frac{5 \pi}{6}$$
$$x_{4} = \frac{7 \pi}{6}$$
$$x_{1} = - \frac{\pi}{6}$$
$$x_{2} = \frac{\pi}{6}$$
$$x_{3} = \frac{5 \pi}{6}$$
$$x_{4} = \frac{7 \pi}{6}$$
This roots
$$x_{1} = - \frac{\pi}{6}$$
$$x_{2} = \frac{\pi}{6}$$
$$x_{3} = \frac{5 \pi}{6}$$
$$x_{4} = \frac{7 \pi}{6}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{\pi}{6} - \frac{1}{10}$$
=
$$- \frac{\pi}{6} - \frac{1}{10}$$
substitute to the expression
$$\sin^{2}{\left(x \right)} < \frac{1}{4}$$
$$\sin^{2}{\left(- \frac{\pi}{6} - \frac{1}{10} \right)} < \frac{1}{4}$$

   2/1    pi\      
sin |-- + --| < 1/4
    \10   6 /      

but

   2/1    pi\      
sin |-- + --| > 1/4
    \10   6 /      

Then
$$x < - \frac{\pi}{6}$$
no execute
one of the solutions of our inequality is:
$$x > - \frac{\pi}{6} \wedge x < \frac{\pi}{6}$$

         _____           _____  
        /     \         /     \  
-------ο-------ο-------ο-------ο-------
       x_1      x_2      x_3      x_4

Other solutions will get with the changeover to the next point
etc.
The answer:
$$x > - \frac{\pi}{6} \wedge x < \frac{\pi}{6}$$
$$x > \frac{5 \pi}{6} \wedge x < \frac{7 \pi}{6}$$