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-4x^2+20x>25 inequation

A inequation with variable

The solution

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- 4*x  + 20*x > 25
4x2+20x>25- 4 x^{2} + 20 x > 25
-4*x^2 + 20*x > 25
Detail solution
Given the inequality:
4x2+20x>25- 4 x^{2} + 20 x > 25
To solve this inequality, we must first solve the corresponding equation:
4x2+20x=25- 4 x^{2} + 20 x = 25
Solve:
Move right part of the equation to
left part with negative sign.

The equation is transformed from
4x2+20x=25- 4 x^{2} + 20 x = 25
to
(4x2+20x)25=0\left(- 4 x^{2} + 20 x\right) - 25 = 0
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
x1=Db2ax_{1} = \frac{\sqrt{D} - b}{2 a}
x2=Db2ax_{2} = \frac{- \sqrt{D} - b}{2 a}
where D = b^2 - 4*a*c - it is the discriminant.
Because
a=4a = -4
b=20b = 20
c=25c = -25
, then
D = b^2 - 4 * a * c = 

(20)^2 - 4 * (-4) * (-25) = 0

Because D = 0, then the equation has one root.
x = -b/2a = -20/2/(-4)

x1=52x_{1} = \frac{5}{2}
x1=52x_{1} = \frac{5}{2}
x1=52x_{1} = \frac{5}{2}
This roots
x1=52x_{1} = \frac{5}{2}
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
x0<x1x_{0} < x_{1}
For example, let's take the point
x0=x1110x_{0} = x_{1} - \frac{1}{10}
=
110+52- \frac{1}{10} + \frac{5}{2}
=
125\frac{12}{5}
substitute to the expression
4x2+20x>25- 4 x^{2} + 20 x > 25
4(125)2+12205>25- 4 \left(\frac{12}{5}\right)^{2} + \frac{12 \cdot 20}{5} > 25
624     
--- > 25
 25     

Then
x<52x < \frac{5}{2}
no execute
the solution of our inequality is:
x>52x > \frac{5}{2}
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Solving inequality on a graph
0123456789-5-4-3-2-110-250250
Rapid solution
This inequality has no solutions