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- Square Inequality Step-by-Step
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-
How to use it?
- Inequation:
- -8x+7,8_<-12,6x+28,5
- 1,5x+1<|x-1|
- 5-(2-x)/4>=2-x
- x-2x+3/2≤x-1/4
- Graphing y =:
- sin(x/4)
- Derivative of:
-
sin(x/4)
- Integral of d{x}:
-
sin(x/4)
-
Identical expressions
- sin(x/ four)< two /sqrt(three)
- sinus of (x divide by 4) less than 2 divide by square root of (3)
- sinus of (x divide by four) less than two divide by square root of (three)
- sin(x/4)<2/√(3)
- sinx/4<2/sqrt3
- sin(x divide by 4)<2 divide by sqrt(3)
-
Similar expressions
- cos(x)>(-2)/sqrt(3)
- sin(x/4-pi/4)>=-sqrt(3)/3
- 3×sinx/4>=2
- -1-2/sqrt(3*cos(x))>0
sin(x/4)<2/sqrt(3) inequation
The solution
You have entered
[src]
/x\ 2
sin|-| < -----
\4/ ___
\/ 3
$$\sin{\left(\frac{x}{4} \right)} < \frac{2}{\sqrt{3}}$$
sin(x/4) < 2/sqrt(3)
Detail solution
Given the inequality:
$$\sin{\left(\frac{x}{4} \right)} < \frac{2}{\sqrt{3}}$$
To solve this inequality, we must first solve the corresponding equation:
$$\sin{\left(\frac{x}{4} \right)} = \frac{2}{\sqrt{3}}$$
Solve:
Given the equation
$$\sin{\left(\frac{x}{4} \right)} = \frac{2}{\sqrt{3}}$$
- this is the simplest trigonometric equation
As right part of the equation
modulo =
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
$$x_{1} = 4 \pi - 4 \operatorname{asin}{\left(\frac{2 \sqrt{3}}{3} \right)}$$
$$x_{2} = 4 \operatorname{asin}{\left(\frac{2 \sqrt{3}}{3} \right)}$$
Exclude the complex solutions:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
$$\sin{\left(\frac{0}{4} \right)} < \frac{2}{\sqrt{3}}$$
so the inequality is always executed
$$\sin{\left(\frac{x}{4} \right)} < \frac{2}{\sqrt{3}}$$
To solve this inequality, we must first solve the corresponding equation:
$$\sin{\left(\frac{x}{4} \right)} = \frac{2}{\sqrt{3}}$$
Solve:
Given the equation
$$\sin{\left(\frac{x}{4} \right)} = \frac{2}{\sqrt{3}}$$
- this is the simplest trigonometric equation
As right part of the equation
modulo =
True
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
$$x_{1} = 4 \pi - 4 \operatorname{asin}{\left(\frac{2 \sqrt{3}}{3} \right)}$$
$$x_{2} = 4 \operatorname{asin}{\left(\frac{2 \sqrt{3}}{3} \right)}$$
Exclude the complex solutions:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\sin{\left(\frac{0}{4} \right)} < \frac{2}{\sqrt{3}}$$
___
2*\/ 3
0 < -------
3
so the inequality is always executed
Solving inequality on a graph