Given the inequality:
$$\frac{\sin{\left(4 x \right)}}{3} > \frac{\sqrt{3}}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\sin{\left(4 x \right)}}{3} = \frac{\sqrt{3}}{2}$$
Solve:
Given the equation
$$\frac{\sin{\left(4 x \right)}}{3} = \frac{\sqrt{3}}{2}$$
- this is the simplest trigonometric equation
Divide both parts of the equation by 1/3
The equation is transformed to
$$\sin{\left(4 x \right)} = \frac{3 \sqrt{3}}{2}$$
As right part of the equation
modulo =
True
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
$$x_{1} = \frac{\pi}{4} - \frac{\operatorname{asin}{\left(\frac{3 \sqrt{3}}{2} \right)}}{4}$$
$$x_{2} = \frac{\operatorname{asin}{\left(\frac{3 \sqrt{3}}{2} \right)}}{4}$$
Exclude the complex solutions:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\sin{\left(0 \cdot 4 \right)}}{3} > \frac{\sqrt{3}}{2}$$
___
\/ 3
0 > -----
2
so the inequality has no solutions