log(3*x-4)<log2*x inequation

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Inequation:
4x²-4x+15≤0
(7x-4)/(x+2)>=1
5*x-1/8>x+2/6
x/3<=1
Graphing y =:
log2*x
Identical expressions
log(three *x- four)<log2*x
logarithm of (3 multiply by x minus 4) less than logarithm of 2 multiply by x
logarithm of (three multiply by x minus four) less than logarithm of 2 multiply by x
log(3x-4)<log2x
log3x-4<log2x
Similar expressions
3log2(x)>3
log(3*x+4)<log2*x
1+13*1/(log3^(x-4))+42*1/(log3^(x))>=0
log((2*x^2+3*x-5)/(x+1))/log(3)<=1
|log3(x-4)|<1
log((2x+4),((x^2)-x))>1
|log(3)*(x-4)|<=1
log2x(x+4)·logx(2-x)≤0

log(3*x - 4) < log(2*x)

$$\log{\left(3 x - 4 \right)} < \log{\left(2 x \right)}$$

log(3*x - 4) < log(2*x)

Solving inequality on a graph

Rapid solution [src]

And(4/3 < x, x < 4)

$$\frac{4}{3} < x \wedge x < 4$$

(4/3 < x)∧(x < 4)

Rapid solution 2 [src]

(4/3, 4)

$$x\ in\ \left(\frac{4}{3}, 4\right)$$

x in Interval.open(4/3, 4)