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Inequation
:
log(5*x^2+3)/log(x^2-6*x+10)^2<=log(4*x^2+7*x+3)/log(x^2-6*x+10)
cos(x)≥1/5
log(2-x)/log(2)*log(2-x)/log(2)+log(absolute(2-x))/log(2)<=2
cos(8x)>0
Derivative of
:
log(3x+2)
Identical expressions
log(3x+ two)=>log(x- one)
logarithm of (3x plus 2) equally greater than logarithm of (x minus 1)
logarithm of (3x plus two) equally greater than logarithm of (x minus one)
log3x+2=>logx-1
Similar expressions
log(3x+2)=>log(x+1)
log3(x+2)(x+4)+log1/3(x+2)<0,5logsqrt(3)7
log3(x+2)>logx+2(81)
log(3x-2)=>log(x-1)
log(3)x+2<log(3)8-x
Solving inequalities
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log(3x+2)=>log(x-1)
log(3x+2)=>log(x-1) inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
log(3*x + 2) >= log(x - 1)
$$\log{\left(3 x + 2 \right)} \geq \log{\left(x - 1 \right)}$$
log(3*x + 2) >= log(x - 1)
Solving inequality on a graph
Rapid solution 2
[src]
(1, oo)
$$x\ in\ \left(1, \infty\right)$$
x in Interval.open(1, oo)
Rapid solution
[src]
And(1 < x, x < oo)
$$1 < x \wedge x < \infty$$
(1 < x)∧(x < oo)