log(3)x+2

+ inequation

Solve the inequality!

A inequation with variable

The solution

You have entered [src]

log(3)*x + 2 < log(3)*8 - x

$$x \log{\left(3 \right)} + 2 < - x + 8 \log{\left(3 \right)}$$

x*log(3) + 2 < -x + 8*log(3)

Solving inequality on a graph

Rapid solution [src]

   /             -2*(1 - 4*log(3))\
And|-oo < x, x < -----------------|
   \                 1 + log(3)   /

$$-\infty < x \wedge x < - \frac{2 \left(1 - 4 \log{\left(3 \right)}\right)}{1 + \log{\left(3 \right)}}$$

(-oo < x)∧(x < -2*(1 - 4*log(3))/(1 + log(3)))

Rapid solution 2 [src]

      -2*(1 - 4*log(3)) 
(-oo, -----------------)
          1 + log(3)    

$$x\ in\ \left(-\infty, - \frac{2 \left(1 - 4 \log{\left(3 \right)}\right)}{1 + \log{\left(3 \right)}}\right)$$

x in Interval.open(-oo, -2*(1 - 4*log(3))/(1 + log(3)))