Given the inequality:
log(3)log(2x+1)<log(3)log(5)To solve this inequality, we must first solve the corresponding equation:
log(3)log(2x+1)=log(3)log(5)Solve:
Given the equation
log(3)log(2x+1)=log(3)log(5)log(3)log(2x+1)=log(3)log(5)Let's divide both parts of the equation by the multiplier of log =1/log(3)
log(2x+1)=log(5)This equation is of the form:
log(v)=p
By definition log
v=e^p
then
2x+1=elog(3)1log(3)1log(5)simplify
2x+1=52x=4x=2x1=2x1=2This roots
x1=2is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
x0<x1For example, let's take the point
x0=x1−101=
−101+2=
1019substitute to the expression
log(3)log(2x+1)<log(3)log(5)log(3)log(1+102⋅19)<log(3)log(5)log(24/5) log(5)
--------- < ------
log(3) log(3)
the solution of our inequality is:
x<2 _____
\
-------ο-------
x1