Given the inequality:
log(3)log(5x−9)≤20To solve this inequality, we must first solve the corresponding equation:
log(3)log(5x−9)=20Solve:
Given the equation
log(3)log(5x−9)=20log(3)log(5x−9)=20Let's divide both parts of the equation by the multiplier of log =1/log(3)
log(5x−9)=20log(3)This equation is of the form:
log(v)=p
By definition log
v=e^p
then
5x−9=elog(3)120simplify
5x−9=34867844015x=3486784410x=697356882x1=697356882x1=697356882This roots
x1=697356882is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
x0≤x1For example, let's take the point
x0=x1−101=
−101+697356882=
106973568819substitute to the expression
log(3)log(5x−9)≤20log(3)log(−9+105⋅6973568819)≤20log(6973568801/2)
----------------- <= 20
log(3)
the solution of our inequality is:
x≤697356882 _____
\
-------•-------
x1