Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
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-
How to use it?
- Inequation:
- 4(x-5)>=3/(x+2)
- 1/3-x/2^2>sqrt(3)
- (x^2+3^x-3)^5>(x^2+9^x-3^x)*5
- 4x−3x**2−9≤0
- Graphing y =:
- ln(x^2+2x+2)
- Derivative of:
- ln(x^2+2x+2)
-
Identical expressions
- ln(x^ two + two x+2)< zero
- ln(x squared plus 2x plus 2) less than 0
- ln(x to the power of two plus two x plus 2) less than zero
- ln(x2+2x+2)<0
- lnx2+2x+2<0
- ln(x²+2x+2)<0
- ln(x to the power of 2+2x+2)<0
- lnx^2+2x+2<0
-
Similar expressions
- ln(x^2-2x+2)<0
- ln(x^2+2x-2)<0
ln(x^2+2x+2)<0 inequation
The solution
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/ 2 \ log\x + 2*x + 2/ < 0
$$\log{\left(x^{2} + 2 x + 2 \right)} < 0$$
log(x^2 + 2*x + 2) < 0
Detail solution
Given the inequality:
$$\log{\left(x^{2} + 2 x + 2 \right)} < 0$$
To solve this inequality, we must first solve the corresponding equation:
$$\log{\left(x^{2} + 2 x + 2 \right)} = 0$$
Solve:
$$x_{1} = -1$$
$$x_{1} = -1$$
This roots
$$x_{1} = -1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-1 - \frac{1}{10}$$
=
$$- \frac{11}{10}$$
substitute to the expression
$$\log{\left(x^{2} + 2 x + 2 \right)} < 0$$
$$\log{\left(2 \left(- \frac{11}{10}\right) + \left(- \frac{11}{10}\right)^{2} + 2 \right)} < 0$$
but
Then
$$x < -1$$
no execute
the solution of our inequality is:
$$x > -1$$
$$\log{\left(x^{2} + 2 x + 2 \right)} < 0$$
To solve this inequality, we must first solve the corresponding equation:
$$\log{\left(x^{2} + 2 x + 2 \right)} = 0$$
Solve:
$$x_{1} = -1$$
$$x_{1} = -1$$
This roots
$$x_{1} = -1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-1 - \frac{1}{10}$$
=
$$- \frac{11}{10}$$
substitute to the expression
$$\log{\left(x^{2} + 2 x + 2 \right)} < 0$$
$$\log{\left(2 \left(- \frac{11}{10}\right) + \left(- \frac{11}{10}\right)^{2} + 2 \right)} < 0$$
/101\ log|---| < 0 \100/
but
/101\ log|---| > 0 \100/
Then
$$x < -1$$
no execute
the solution of our inequality is:
$$x > -1$$
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x_1
Solving inequality on a graph
The graph