Given the inequality:
$$\left(- 3 x^{2} + 4 x\right) - 9 \leq 0$$
To solve this inequality, we must first solve the corresponding equation:
$$\left(- 3 x^{2} + 4 x\right) - 9 = 0$$
Solve:
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -3$$
$$b = 4$$
$$c = -9$$
, then
D = b^2 - 4 * a * c =
(4)^2 - 4 * (-3) * (-9) = -92
Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \frac{2}{3} - \frac{\sqrt{23} i}{3}$$
$$x_{2} = \frac{2}{3} + \frac{\sqrt{23} i}{3}$$
$$x_{1} = \frac{2}{3} - \frac{\sqrt{23} i}{3}$$
$$x_{2} = \frac{2}{3} + \frac{\sqrt{23} i}{3}$$
Exclude the complex solutions:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$-9 + \left(0 \cdot 4 - 3 \cdot 0^{2}\right) \leq 0$$
-9 <= 0
so the inequality is always executed