4(x-5)>=3/(x+2) inequation

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               3  
4*(x - 5) >= -----
             x + 2

$$4 \left(x - 5\right) \geq \frac{3}{x + 2}$$

4*(x - 5) >= 3/(x + 2)

Solving inequality on a graph

Rapid solution [src]

  /   /3     ____             \  3     ____     \
Or|And|- - \/ 13  <= x, x < -2|, - + \/ 13  <= x|
  \   \2                      /  2              /

$$\left(\frac{3}{2} - \sqrt{13} \leq x \wedge x < -2\right) \vee \frac{3}{2} + \sqrt{13} \leq x$$

(3/2 + sqrt(13) <= x)∨((x < -2)∧(3/2 - sqrt(13) <= x))

Rapid solution 2 [src]

 3     ____         3     ____     
[- - \/ 13 , -2) U [- + \/ 13 , oo)
 2                  2

$$x\ in\ \left[\frac{3}{2} - \sqrt{13}, -2\right) \cup \left[\frac{3}{2} + \sqrt{13}, \infty\right)$$

x in Union(Interval.Ropen(3/2 - sqrt(13), -2), Interval(3/2 + sqrt(13), oo))