3 _______ 3 _______ \/ x + 1 > \/ 3 - x
(x + 1)^(1/3) > (3 - x)^(1/3)
(1, oo)
x in Interval.open(1, oo)
And(1 < x, x < oo)
(1 < x)∧(x < oo)