Mister Exam
cbrt(x+10)>10-x inequation
The solution
You have entered
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3 ________ \/ x + 10 > 10 - x
$$\sqrt[3]{x + 10} > 10 - x$$
(x + 10)^(1/3) > 10 - x
Solving inequality on a graph
Rapid solution
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__________________
3 / ______
1 \/ 270 + 3*\/ 8103
10 + --------------------- - --------------------- < x
__________________ 3
3 / ______
\/ 270 + 3*\/ 8103
$$- \frac{\sqrt[3]{270 + 3 \sqrt{8103}}}{3} + \frac{1}{\sqrt[3]{270 + 3 \sqrt{8103}}} + 10 < x$$
-(270 + 3*sqrt(8103))^(1/3)/3 + (270 + 3*sqrt(8103))^(-1/3) + 10 < x
Rapid solution 2
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3 ___ 3 / ______ 2/3
\/ 3 *\/ 90 + \/ 8103 3
(10 - ------------------------ + --------------------, oo)
3 _______________
3 / ______
3*\/ 90 + \/ 8103
$$x\ in\ \left(- \frac{\sqrt[3]{3} \sqrt[3]{90 + \sqrt{8103}}}{3} + \frac{3^{\frac{2}{3}}}{3 \sqrt[3]{90 + \sqrt{8103}}} + 10, \infty\right)$$
x in Interval.open(-3^(1/3)*(90 + sqrt(8103))^(1/3)/3 + 3^(2/3)/(3*(90 + sqrt(8103))^(1/3)) + 10, oo)