Mister Exam

Lang:

How to use it?
Inequation:
(abs((x+2)/(x-6)))<=(abs((x+2)/(x-3)))
x^2-4x+6<0
(1/2)^(x+2)>4
(x+2)^3<1
Identical expressions
(abs((x+ two)/(x- six)))<=(abs((x+ two)/(x- three)))
(abs((x plus 2) divide by (x minus 6))) less than or equal to (abs((x plus 2) divide by (x minus 3)))
(abs((x plus two) divide by (x minus six))) less than or equal to (abs((x plus two) divide by (x minus three)))
absx+2/x-6<=absx+2/x-3
(abs((x+2) divide by (x-6)))<=(abs((x+2) divide by (x-3)))
Similar expressions
(abs((x+2)/(x+6)))<=(abs((x+2)/(x-3)))
(abs((x+2)/(x-6)))<=(abs((x-2)/(x-3)))
(abs((x+2)/(x-6)))<=(abs((x+2)/(x+3)))
(abs((x-2)/(x-6)))<=(abs((x+2)/(x-3)))

(abs((x+2)/(x-6)))<=(abs((x+2)/(x-3))) inequation

You have entered [src]

|x + 2|    |x + 2|
|-----| <= |-----|
|x - 6|    |x - 3|

$$\left|{\frac{x + 2}{x - 6}}\right| \leq \left|{\frac{x + 2}{x - 3}}\right|$$

Abs((x + 2)/(x - 6)) <= Abs((x + 2)/(x - 3))

Solving inequality on a graph

Rapid solution [src]

Or(And(x <= 9/2, 3 < x), And(-oo < x, x < 3))

$$\left(x \leq \frac{9}{2} \wedge 3 < x\right) \vee \left(-\infty < x \wedge x < 3\right)$$

((x <= 9/2)∧(3 < x))∨((-oo < x)∧(x < 3))

Rapid solution 2 [src]

(-oo, 3) U (3, 9/2]

$$x\ in\ \left(-\infty, 3\right) \cup \left(3, \frac{9}{2}\right]$$

x in Union(Interval.open(-oo, 3), Interval.Lopen(3, 9/2))