Mister Exam

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Inequation:
4x−3x**2−9≤0
(x+-3)/x+1(2x+4)_>0
(x+2)^3<1
16^x-9<1
Identical expressions
(6x(two -x)+x^(three)- eight)/(| two -3x|)<=\sqrt(3x- two)
(6x(2 minus x) plus x to the power of (3) minus 8) divide by ( module of 2 minus 3x|) less than or equal to \ square root of (3x minus 2)
(6x(two minus x) plus x to the power of (three) minus eight) divide by ( module of two minus 3x|) less than or equal to \ square root of (3x minus two)
(6x(2-x)+x^(3)-8)/(|2-3x|)<=\√(3x-2)
(6x(2-x)+x(3)-8)/(|2-3x|)<=\sqrt(3x-2)
6x2-x+x3-8/|2-3x|<=\sqrt3x-2
6x2-x+x^3-8/|2-3x|<=\sqrt3x-2
(6x(2-x)+x^(3)-8) divide by (|2-3x|)<=\sqrt(3x-2)
Similar expressions
(6x(2-x)+x^(3)-8)/(|2+3x|)<=\sqrt(3x-2)
(6x(2-x)+x^(3)-8)/(|2-3x|)<=\sqrt(3x+2)
(6x(2+x)+x^(3)-8)/(|2-3x|)<=\sqrt(3x-2)
(6x(2-x)-x^(3)-8)/(|2-3x|)<=\sqrt(3x-2)
(6x(2-x)+x^(3)+8)/(|2-3x|)<=\sqrt(3x-2)

(6x(2-x)+x^(3)-8)/(|2-3x|)<=\sqrt(3x-2) inequation

You have entered [src]

               3                   
6*x*(2 - x) + x  - 8      _________
-------------------- <= \/ 3*x - 2 
     |2 - 3*x|

$$\frac{\left(x^{3} + 6 x \left(2 - x\right)\right) - 8}{\left|{2 - 3 x}\right|} \leq \sqrt{3 x - 2}$$

(x^3 + (6*x)*(2 - x) - 8)/|2 - 3*x| <= sqrt(3*x - 2)

Rapid solution [src]

And(x <= 6, 2/3 < x)

$$x \leq 6 \wedge \frac{2}{3} < x$$

(x <= 6)∧(2/3 < x)

Rapid solution 2 [src]

(2/3, 6]

$$x\ in\ \left(\frac{2}{3}, 6\right]$$

x in Interval.Lopen(2/3, 6)