Given the inequality:
2sin(x)≤1To solve this inequality, we must first solve the corresponding equation:
2sin(x)=1Solve:
Given the equation
2sin(x)=1- this is the simplest trigonometric equation
Divide both parts of the equation by 2
The equation is transformed to
sin(x)=21This equation is transformed to
x=2πn+asin(21)x=2πn−asin(21)+πOr
x=2πn+6πx=2πn+65π, where n - is a integer
x1=2πn+6πx2=2πn+65πx1=2πn+6πx2=2πn+65πThis roots
x1=2πn+6πx2=2πn+65πis the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
x0≤x1For example, let's take the point
x0=x1−101=
(2πn+6π)+−101=
2πn−101+6πsubstitute to the expression
2sin(x)≤12sin(2πn−101+6π)≤1 / 1 pi \
2*sin|- -- + -- + 2*pi*n| <= 1
\ 10 6 /
one of the solutions of our inequality is:
x≤2πn+6π _____ _____
\ /
-------•-------•-------
x1 x2
Other solutions will get with the changeover to the next point
etc.
The answer:
x≤2πn+6πx≥2πn+65π