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2sinx
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Integral of 2sinx dx

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The solution

You have entered [src] 
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 |  2*sin(x) dx
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∫012sin⁡(x) dx\int\limits_{0}^{1} 2 \sin{\left(x \right)}\, dx 
Integral(2*sin(x), (x, 0, 1))
Detail solution

  1. The integral of a constant times a function is the constant times the integral of the function:

    ∫2sin⁡(x) dx=2∫sin⁡(x) dx\int 2 \sin{\left(x \right)}\, dx = 2 \int \sin{\left(x \right)}\, dx

    1. The integral of sine is negative cosine:

      ∫sin⁡(x) dx=−cos⁡(x)\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}

    So, the result is: −2cos⁡(x)- 2 \cos{\left(x \right)}

  2. Add the constant of integration:

    −2cos⁡(x)+constant- 2 \cos{\left(x \right)}+ \mathrm{constant}

The answer is:

−2cos⁡(x)+constant- 2 \cos{\left(x \right)}+ \mathrm{constant}

The answer (Indefinite) [src] 
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 | 2*sin(x) dx = C - 2*cos(x)
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∫2sin⁡(x) dx=C−2cos⁡(x)\int 2 \sin{\left(x \right)}\, dx = C - 2 \cos{\left(x \right)}
Simplify
The graph
0.001.000.100.200.300.400.500.600.700.800.905-5
Plot the graph f(x)
The answer [src] 
2 - 2*cos(1)
2−2cos⁡(1)2 - 2 \cos{\left(1 \right)} 
=
= 
2 - 2*cos(1)
2−2cos⁡(1)2 - 2 \cos{\left(1 \right)} 
2 - 2*cos(1)
Numerical answer [src] 
0.919395388263721
0.919395388263721
The graph
Integral of 2sinx dx

    Use the examples entering the upper and lower limits of integration.

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