Integral of 2sinx dx

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$$\int\limits_{0}^{1} 2 \sin{\left(x \right)}\, dx$$

Integral(2*sin(x), (x, 0, 1))

Detail solution

The integral of a constant times a function is the constant times the integral of the function:

$\int 2 \sin{\left(x \right)}\, dx = 2 \int \sin{\left(x \right)}\, dx$
1. The integral of sine is negative cosine:
  
  $\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}$
So, the result is: $- 2 \cos{\left(x \right)}$
Add the constant of integration:

$- 2 \cos{\left(x \right)}+ \mathrm{constant}$

The answer is:

$- 2 \cos{\left(x \right)}+ \mathrm{constant}$

The answer (Indefinite) [src]

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 | 2*sin(x) dx = C - 2*cos(x)
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$$\int 2 \sin{\left(x \right)}\, dx = C - 2 \cos{\left(x \right)}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

2 - 2*cos(1)

$$2 - 2 \cos{\left(1 \right)}$$

2 - 2*cos(1)

$$2 - 2 \cos{\left(1 \right)}$$

2 - 2*cos(1)

Numerical answer [src]

0.919395388263721

0.919395388263721

The graph

Use the examples entering the upper and lower limits of integration.