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Graphing y = sqrt(sqr(log(x)-1))

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = \/  (log(x) - 1)  
f(x)=(log(x)1)2f{\left(x \right)} = \sqrt{\left(\log{\left(x \right)} - 1\right)^{2}}
f = sqrt((log(x) - 1)^2)
The graph of the function
02468-8-6-4-2-101005
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
(log(x)1)2=0\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}} = 0
Solve this equation
The points of intersection with the axis X:

Analytical solution
x1=ex_{1} = e
Numerical solution
x1=2.71828182845905x_{1} = 2.71828182845905
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to sqrt((log(x) - 1)^2).
(log(0)1)2\sqrt{\left(\log{\left(0 \right)} - 1\right)^{2}}
The result:
f(0)=~f{\left(0 \right)} = \tilde{\infty}
sof doesn't intersect Y
Extrema of the function
In order to find the extrema, we need to solve the equation
ddxf(x)=0\frac{d}{d x} f{\left(x \right)} = 0
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
ddxf(x)=\frac{d}{d x} f{\left(x \right)} =
the first derivative
(log(x)1)2x(log(x)1)=0\frac{\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}}}{x \left(\log{\left(x \right)} - 1\right)} = 0
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dx2f(x)=0\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dx2f(x)=\frac{d^{2}}{d x^{2}} f{\left(x \right)} =
the second derivative
(log(x)1)2x2(log(x)1)=0- \frac{\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}}}{x^{2} \left(\log{\left(x \right)} - 1\right)} = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
limx(log(x)1)2=\lim_{x \to -\infty} \sqrt{\left(\log{\left(x \right)} - 1\right)^{2}} = \infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
limx(log(x)1)2=\lim_{x \to \infty} \sqrt{\left(\log{\left(x \right)} - 1\right)^{2}} = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt((log(x) - 1)^2), divided by x at x->+oo and x ->-oo
limx((log(x)1)2x)=0\lim_{x \to -\infty}\left(\frac{\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}}}{x}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
limx((log(x)1)2x)=0\lim_{x \to \infty}\left(\frac{\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}}}{x}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
(log(x)1)2=(log(x)1)2\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}} = \sqrt{\left(\log{\left(- x \right)} - 1\right)^{2}}
- No
(log(x)1)2=(log(x)1)2\sqrt{\left(\log{\left(x \right)} - 1\right)^{2}} = - \sqrt{\left(\log{\left(- x \right)} - 1\right)^{2}}
- No
so, the function
not is
neither even, nor odd