Mister Exam
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-
How to use it?
- Graphing y =:
- (4x^2+1)/x
- (6-x^3)/(x^2)
- x+cosx
- x^4-2*x^3+1
- Integral of d{x}:
-
1/(x+1)^3
- Derivative of:
-
1/(x+1)^3
-
Identical expressions
- one /(x+ one)^ three
- 1 divide by (x plus 1) cubed
- one divide by (x plus one) to the power of three
- 1/(x+1)3
- 1/x+13
- 1/(x+1)³
- 1/(x+1) to the power of 3
- 1/x+1^3
- 1 divide by (x+1)^3
-
Similar expressions
- 1/(x-1)^3
Graphing y = 1/(x+1)^3
The solution
You have entered
[src]
1
f(x) = --------
3
(x + 1)
$$f{\left(x \right)} = \frac{1}{\left(x + 1\right)^{3}}$$
f = 1/((x + 1)^3)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -1$$
$$x_{1} = -1$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{1}{\left(x + 1\right)^{3}} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$\frac{1}{\left(x + 1\right)^{3}} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{3}{\left(x + 1\right) \left(x + 1\right)^{3}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{3}{\left(x + 1\right) \left(x + 1\right)^{3}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{12}{\left(x + 1\right)^{5}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{12}{\left(x + 1\right)^{5}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = -1$$
$$x_{1} = -1$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \frac{1}{\left(x + 1\right)^{3}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \frac{1}{\left(x + 1\right)^{3}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty} \frac{1}{\left(x + 1\right)^{3}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \frac{1}{\left(x + 1\right)^{3}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 1/((x + 1)^3), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{1}{x \left(x + 1\right)^{3}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{x \left(x + 1\right)^{3}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{1}{x \left(x + 1\right)^{3}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{x \left(x + 1\right)^{3}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{1}{\left(x + 1\right)^{3}} = \frac{1}{\left(1 - x\right)^{3}}$$
- No
$$\frac{1}{\left(x + 1\right)^{3}} = - \frac{1}{\left(1 - x\right)^{3}}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\frac{1}{\left(x + 1\right)^{3}} = \frac{1}{\left(1 - x\right)^{3}}$$
- No
$$\frac{1}{\left(x + 1\right)^{3}} = - \frac{1}{\left(1 - x\right)^{3}}$$
- No
so, the function
not is
neither even, nor odd