Mister Exam
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-
How to use it?
- Graphing y =:
- x^3-((x^4)/4)
- x^3-2*x^2+x
- x^2+x-1
- (x^2-1)/(x-1)
- Integral of d{x}:
-
1/(2x-1)
- Sum of series:
- 1/(2x-1)
-
Identical expressions
- one /(2x- one)
- 1 divide by (2x minus 1)
- one divide by (2x minus one)
- 1/2x-1
- 1 divide by (2x-1)
-
Similar expressions
- log(1/2)x-1
- (x-1)/(2x-1)
- 1/2^log1/2(x-1)
- exp^((2*(x-1)))/(2*(x-1))
- 1/(2x+1)
- exp(2*(x-1)/2*(x-1))
Graphing y = 1/(2x-1)
The solution
You have entered
[src]
1
f(x) = 1*-------
2*x - 1
$$f{\left(x \right)} = 1 \cdot \frac{1}{2 x - 1}$$
f = 1/(2*x - 1*1)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0.5$$
$$x_{1} = 0.5$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$1 \cdot \frac{1}{2 x - 1} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$1 \cdot \frac{1}{2 x - 1} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{2}{\left(2 x - 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{2}{\left(2 x - 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{8}{\left(2 x - 1\right)^{3}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{8}{\left(2 x - 1\right)^{3}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 0.5$$
$$x_{1} = 0.5$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(1 \cdot \frac{1}{2 x - 1}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(1 \cdot \frac{1}{2 x - 1}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty}\left(1 \cdot \frac{1}{2 x - 1}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(1 \cdot \frac{1}{2 x - 1}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 1/(2*x - 1*1), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{1}{x \left(2 x - 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{x \left(2 x - 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{1}{x \left(2 x - 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{x \left(2 x - 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$1 \cdot \frac{1}{2 x - 1} = \frac{1}{- 2 x - 1}$$
- No
$$1 \cdot \frac{1}{2 x - 1} = - \frac{1}{- 2 x - 1}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$1 \cdot \frac{1}{2 x - 1} = \frac{1}{- 2 x - 1}$$
- No
$$1 \cdot \frac{1}{2 x - 1} = - \frac{1}{- 2 x - 1}$$
- No
so, the function
not is
neither even, nor odd
The graph