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  • Graphing y =:
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  • (x^2-4x+1)/(x-4)
  • Identical expressions

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  • 1/2log1/2(x-1)
  • 1/2log1/2x-1
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  • 1 divide by 2^log1 divide by 2(x-1)
  • Similar expressions

  • 1/2^log1/2(x+1)

Graphing y = 1/2^log1/2(x-1)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
        -log(1)        
       2               
f(x) = --------*(x - 1)
          2            
$$f{\left(x \right)} = \frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right)$$
f = ((1/2)^log(1)/2)*(x - 1)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right) = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 1$$
Numerical solution
$$x_{1} = 1$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to ((1/2)^log(1)/2)*(x - 1).
$$\left(-1\right) \frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2}$$
The result:
$$f{\left(0 \right)} = - \frac{1}{2}$$
The point:
(0, -1/2)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right)\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right)\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of ((1/2)^log(1)/2)*(x - 1), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{2^{- \log{\left(1 \right)}} \left(x - 1\right)}{2 x}\right) = \frac{1}{2}$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = \frac{x}{2}$$
$$\lim_{x \to \infty}\left(\frac{2^{- \log{\left(1 \right)}} \left(x - 1\right)}{2 x}\right) = \frac{1}{2}$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = \frac{x}{2}$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right) = \frac{2^{- \log{\left(1 \right)}} \left(- x - 1\right)}{2}$$
- No
$$\frac{\left(\frac{1}{2}\right)^{\log{\left(1 \right)}}}{2} \left(x - 1\right) = - \frac{2^{- \log{\left(1 \right)}} \left(- x - 1\right)}{2}$$
- No
so, the function
not is
neither even, nor odd