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Graphing y = log(2)(3*x+4)

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = log(2)*(3*x + 4)
f(x)=(3x+4)log(2)f{\left(x \right)} = \left(3 x + 4\right) \log{\left(2 \right)}
f = (3*x + 4)*log(2)
The graph of the function
02468-8-6-4-2-1010-5050
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
(3x+4)log(2)=0\left(3 x + 4\right) \log{\left(2 \right)} = 0
Solve this equation
The points of intersection with the axis X:

Analytical solution
x1=43x_{1} = - \frac{4}{3}
Numerical solution
x1=1.33333333333333x_{1} = -1.33333333333333
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to log(2)*(3*x + 4).
(03+4)log(2)\left(0 \cdot 3 + 4\right) \log{\left(2 \right)}
The result:
f(0)=4log(2)f{\left(0 \right)} = 4 \log{\left(2 \right)}
The point:
(0, 4*log(2))
Extrema of the function
In order to find the extrema, we need to solve the equation
ddxf(x)=0\frac{d}{d x} f{\left(x \right)} = 0
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
ddxf(x)=\frac{d}{d x} f{\left(x \right)} =
the first derivative
3log(2)=03 \log{\left(2 \right)} = 0
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dx2f(x)=0\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dx2f(x)=\frac{d^{2}}{d x^{2}} f{\left(x \right)} =
the second derivative
0=00 = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
limx((3x+4)log(2))=\lim_{x \to -\infty}\left(\left(3 x + 4\right) \log{\left(2 \right)}\right) = -\infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
limx((3x+4)log(2))=\lim_{x \to \infty}\left(\left(3 x + 4\right) \log{\left(2 \right)}\right) = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of log(2)*(3*x + 4), divided by x at x->+oo and x ->-oo
limx((3x+4)log(2)x)=3log(2)\lim_{x \to -\infty}\left(\frac{\left(3 x + 4\right) \log{\left(2 \right)}}{x}\right) = 3 \log{\left(2 \right)}
Let's take the limit
so,
inclined asymptote equation on the left:
y=3xlog(2)y = 3 x \log{\left(2 \right)}
limx((3x+4)log(2)x)=3log(2)\lim_{x \to \infty}\left(\frac{\left(3 x + 4\right) \log{\left(2 \right)}}{x}\right) = 3 \log{\left(2 \right)}
Let's take the limit
so,
inclined asymptote equation on the right:
y=3xlog(2)y = 3 x \log{\left(2 \right)}
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
(3x+4)log(2)=(43x)log(2)\left(3 x + 4\right) \log{\left(2 \right)} = \left(4 - 3 x\right) \log{\left(2 \right)}
- No
(3x+4)log(2)=(43x)log(2)\left(3 x + 4\right) \log{\left(2 \right)} = - \left(4 - 3 x\right) \log{\left(2 \right)}
- No
so, the function
not is
neither even, nor odd