Mister Exam
Graphing y = log(3)((9x-1)/(x+2))
The solution
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9*x - 1
f(x) = log(3)*-------
x + 2
$$f{\left(x \right)} = \frac{9 x - 1}{x + 2} \log{\left(3 \right)}$$
f = ((9*x - 1)/(x + 2))*log(3)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -2$$
$$x_{1} = -2$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = \frac{1}{9}$$
Numerical solution
$$x_{1} = 0.111111111111111$$
so we need to solve the equation:
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = \frac{1}{9}$$
Numerical solution
$$x_{1} = 0.111111111111111$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\left(\frac{9}{x + 2} - \frac{9 x - 1}{\left(x + 2\right)^{2}}\right) \log{\left(3 \right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\left(\frac{9}{x + 2} - \frac{9 x - 1}{\left(x + 2\right)^{2}}\right) \log{\left(3 \right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{2 \left(9 - \frac{9 x - 1}{x + 2}\right) \log{\left(3 \right)}}{\left(x + 2\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{2 \left(9 - \frac{9 x - 1}{x + 2}\right) \log{\left(3 \right)}}{\left(x + 2\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = -2$$
$$x_{1} = -2$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{9 x - 1}{x + 2} \log{\left(3 \right)}\right) = 9 \log{\left(3 \right)}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 9 \log{\left(3 \right)}$$
$$\lim_{x \to \infty}\left(\frac{9 x - 1}{x + 2} \log{\left(3 \right)}\right) = 9 \log{\left(3 \right)}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 9 \log{\left(3 \right)}$$
$$\lim_{x \to -\infty}\left(\frac{9 x - 1}{x + 2} \log{\left(3 \right)}\right) = 9 \log{\left(3 \right)}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 9 \log{\left(3 \right)}$$
$$\lim_{x \to \infty}\left(\frac{9 x - 1}{x + 2} \log{\left(3 \right)}\right) = 9 \log{\left(3 \right)}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 9 \log{\left(3 \right)}$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of log(3)*((9*x - 1)/(x + 2)), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\left(9 x - 1\right) \log{\left(3 \right)}}{x \left(x + 2\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\left(9 x - 1\right) \log{\left(3 \right)}}{x \left(x + 2\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{\left(9 x - 1\right) \log{\left(3 \right)}}{x \left(x + 2\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\left(9 x - 1\right) \log{\left(3 \right)}}{x \left(x + 2\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = \frac{\left(- 9 x - 1\right) \log{\left(3 \right)}}{2 - x}$$
- No
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = - \frac{\left(- 9 x - 1\right) \log{\left(3 \right)}}{2 - x}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = \frac{\left(- 9 x - 1\right) \log{\left(3 \right)}}{2 - x}$$
- No
$$\frac{9 x - 1}{x + 2} \log{\left(3 \right)} = - \frac{\left(- 9 x - 1\right) \log{\left(3 \right)}}{2 - x}$$
- No
so, the function
not is
neither even, nor odd