Mister Exam

Graphing y = lnt

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(t) = log(t)
f(t)=log(t)f{\left(t \right)} = \log{\left(t \right)}
f = log(t)
The graph of the function
02468-8-6-4-2-10105-5
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis T at f = 0
so we need to solve the equation:
log(t)=0\log{\left(t \right)} = 0
Solve this equation
The points of intersection with the axis T:

Analytical solution
t1=1t_{1} = 1
Numerical solution
t1=1t_{1} = 1
The points of intersection with the Y axis coordinate
The graph crosses Y axis when t equals 0:
substitute t = 0 to log(t).
log(0)\log{\left(0 \right)}
The result:
f(0)=~f{\left(0 \right)} = \tilde{\infty}
sof doesn't intersect Y
Extrema of the function
In order to find the extrema, we need to solve the equation
ddtf(t)=0\frac{d}{d t} f{\left(t \right)} = 0
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
ddtf(t)=\frac{d}{d t} f{\left(t \right)} =
the first derivative
1t=0\frac{1}{t} = 0
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dt2f(t)=0\frac{d^{2}}{d t^{2}} f{\left(t \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dt2f(t)=\frac{d^{2}}{d t^{2}} f{\left(t \right)} =
the second derivative
1t2=0- \frac{1}{t^{2}} = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at t->+oo and t->-oo
limtlog(t)=\lim_{t \to -\infty} \log{\left(t \right)} = \infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
limtlog(t)=\lim_{t \to \infty} \log{\left(t \right)} = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of log(t), divided by t at t->+oo and t ->-oo
limt(log(t)t)=0\lim_{t \to -\infty}\left(\frac{\log{\left(t \right)}}{t}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
limt(log(t)t)=0\lim_{t \to \infty}\left(\frac{\log{\left(t \right)}}{t}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-t) и f = -f(-t).
So, check:
log(t)=log(t)\log{\left(t \right)} = \log{\left(- t \right)}
- No
log(t)=log(t)\log{\left(t \right)} = - \log{\left(- t \right)}
- No
so, the function
not is
neither even, nor odd