Mister Exam
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-
How to use it?
- Graphing y =:
-
x/x^2+1
- x/(x^2-1)
- xe^(1/x)
- xcosx
-
Identical expressions
- (abs((two - three *x)/(two -x)))
- (abs((2 minus 3 multiply by x) divide by (2 minus x)))
- (abs((two minus three multiply by x) divide by (two minus x)))
- (abs((2-3x)/(2-x)))
- abs2-3x/2-x
- (abs((2-3*x) divide by (2-x)))
-
Similar expressions
- (abs((2-3*x)/(2+x)))
- (abs((2+3*x)/(2-x)))
Graphing y = (abs((2-3*x)/(2-x)))
The solution
You have entered
[src]
|2 - 3*x|
f(x) = |-------|
| 2 - x |
$$f{\left(x \right)} = \left|{\frac{2 - 3 x}{2 - x}}\right|$$
f = Abs((2 - 3*x)/(2 - x))
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 2$$
$$x_{1} = 2$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = 0$$
Solve this equation
The points of intersection with the axis X:
Numerical solution
$$x_{1} = 0.666666666666667$$
so we need to solve the equation:
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = 0$$
Solve this equation
The points of intersection with the axis X:
Numerical solution
$$x_{1} = 0.666666666666667$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{\left(2 - 3 x\right) \left(x - 2\right) \left(\frac{2 - 3 x}{\left(2 - x\right)^{2}} - \frac{3}{2 - x}\right) \operatorname{sign}{\left(\frac{3 x - 2}{x - 2} \right)}}{\left(2 - x\right) \left(3 x - 2\right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{\left(2 - 3 x\right) \left(x - 2\right) \left(\frac{2 - 3 x}{\left(2 - x\right)^{2}} - \frac{3}{2 - x}\right) \operatorname{sign}{\left(\frac{3 x - 2}{x - 2} \right)}}{\left(2 - x\right) \left(3 x - 2\right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Vertical asymptotes
Have:
$$x_{1} = 2$$
$$x_{1} = 2$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \left|{\frac{2 - 3 x}{2 - x}}\right| = 3$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 3$$
$$\lim_{x \to \infty} \left|{\frac{2 - 3 x}{2 - x}}\right| = 3$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 3$$
$$\lim_{x \to -\infty} \left|{\frac{2 - 3 x}{2 - x}}\right| = 3$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 3$$
$$\lim_{x \to \infty} \left|{\frac{2 - 3 x}{2 - x}}\right| = 3$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 3$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of Abs((2 - 3*x)/(2 - x)), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\left|{\frac{2 - 3 x}{2 - x}}\right|}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\left|{\frac{2 - 3 x}{2 - x}}\right|}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{\left|{\frac{2 - 3 x}{2 - x}}\right|}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\left|{\frac{2 - 3 x}{2 - x}}\right|}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = \left|{\frac{3 x + 2}{x + 2}}\right|$$
- No
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = - \left|{\frac{3 x + 2}{x + 2}}\right|$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = \left|{\frac{3 x + 2}{x + 2}}\right|$$
- No
$$\left|{\frac{2 - 3 x}{2 - x}}\right| = - \left|{\frac{3 x + 2}{x + 2}}\right|$$
- No
so, the function
not is
neither even, nor odd