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  • Graphing y =:
  • (x+5)/(x^2-25)
  • x^3-2x^2-x
  • x^3-12x-7
  • x^2+6x-3
  • Identical expressions

  • (x+ five)/(x^ two - twenty-five)
  • (x plus 5) divide by (x squared minus 25)
  • (x plus five) divide by (x to the power of two minus twenty minus five)
  • (x+5)/(x2-25)
  • x+5/x2-25
  • (x+5)/(x²-25)
  • (x+5)/(x to the power of 2-25)
  • x+5/x^2-25
  • (x+5) divide by (x^2-25)
  • Similar expressions

  • (x+5)/(x^2+25)
  • (x-5)/(x^2-25)

Graphing y = (x+5)/(x^2-25)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
        x + 5 
f(x) = -------
        2     
       x  - 25
$$f{\left(x \right)} = \frac{x + 5}{x^{2} - 25}$$
f = (x + 5)/(x^2 - 25)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -5$$
$$x_{2} = 5$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{x + 5}{x^{2} - 25} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to (x + 5)/(x^2 - 25).
$$\frac{5}{-25 + 0^{2}}$$
The result:
$$f{\left(0 \right)} = - \frac{1}{5}$$
The point:
(0, -1/5)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{2 x \left(x + 5\right)}{\left(x^{2} - 25\right)^{2}} + \frac{1}{x^{2} - 25} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(- 2 x + \left(x + 5\right) \left(\frac{4 x^{2}}{x^{2} - 25} - 1\right)\right)}{\left(x^{2} - 25\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = -5$$
$$x_{2} = 5$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{x + 5}{x^{2} - 25}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{x + 5}{x^{2} - 25}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (x + 5)/(x^2 - 25), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{x + 5}{x \left(x^{2} - 25\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{x + 5}{x \left(x^{2} - 25\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{x + 5}{x^{2} - 25} = \frac{5 - x}{x^{2} - 25}$$
- No
$$\frac{x + 5}{x^{2} - 25} = - \frac{5 - x}{x^{2} - 25}$$
- No
so, the function
not is
neither even, nor odd