Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x-2)^2+(x-3)^2=2x^2
- Equation (x^2-81)^2+(x^2+5x-36)^2=0
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Equation 3x-3=7x-3(2x-5)
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Equation 9+6x-8x^2=0
- Express {x} in terms of y where:
- 9*x-18*y=6
- 4*x+13*y=13
- -1*x+19*y=-10
- -10*x+18*y=6
- Graphing y =:
- 3x-3
- Derivative of:
- 3x-3
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Identical expressions
- three x- three =7x-3(2x- five)
- 3x minus 3 equally 7x minus 3(2x minus 5)
- three x minus three equally 7x minus 3(2x minus five)
- 3x-3=7x-32x-5
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Similar expressions
- 7*x-3*(2*x-5)=0
- 3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=28
- 3x-3=7x+3(2x-5)
- 3x-3=7x-3*(2x-5)
- 3x+3=7x-3(2x-5)
- -x-2+3*(x-3)=3*(4-x)-3
- y^n+y=2*cos(3x)-3*sin(3x)
- 3x-3=7x-3(2x+5)
- 32*x-7*x-32*x-5+35=33*x
- -x-2+3(x-3)=3(4-x)-3
- 3*x-37*x-3*(2*x-5)=0
3x-3=7x-3(2x-5) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 2
We get the answer: x = 9
3*x-3 = 7*x-3*(2*x-5)
Expand brackets in the right part
3*x-3 = 7*x-3*2*x+3*5
Looking for similar summands in the right part:
-3 + 3*x = 15 + x
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 2
x = 18 / (2)
We get the answer: x = 9
The graph