3a^2-21=0 equation
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The solution
Detail solution
This equation is of the form
a*a^2 + b*a + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$a_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$a_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 3$$
$$b = 0$$
$$c = -21$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (3) * (-21) = 252
Because D > 0, then the equation has two roots.
a1 = (-b + sqrt(D)) / (2*a)
a2 = (-b - sqrt(D)) / (2*a)
or
$$a_{1} = \sqrt{7}$$
$$a_{2} = - \sqrt{7}$$
Vieta's Theorem
rewrite the equation
$$3 a^{2} - 21 = 0$$
of
$$a^{3} + a b + c = 0$$
as reduced quadratic equation
$$a^{2} + b + \frac{c}{a} = 0$$
$$a^{2} - 7 = 0$$
$$a^{2} + a p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = -7$$
Vieta Formulas
$$a_{1} + a_{2} = - p$$
$$a_{1} a_{2} = q$$
$$a_{1} + a_{2} = 0$$
$$a_{1} a_{2} = -7$$
$$a_{1} = - \sqrt{7}$$
$$a_{2} = \sqrt{7}$$
Sum and product of roots
[src]
$$- \sqrt{7} + \sqrt{7}$$
$$0$$
$$- \sqrt{7} \sqrt{7}$$
$$-7$$