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- Equation:
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Equation 16+6x=5(1-2x)-13
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Equation ctgx=1
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Equation sin^2((x/4)+(pi/4))*sin^2((x/4)-(pi/4))=0,375sin^2(-(pi/4))
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Identical expressions
- sixteen +6x= five (one -2x)- thirteen
- 16 plus 6x equally 5(1 minus 2x) minus 13
- sixteen plus 6x equally five (one minus 2x) minus thirteen
- 16+6x=51-2x-13
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Similar expressions
- 16+6x=5*(1-2x)-13
- 16+6x=5(1-2x)+13
- 16-6x=5(1-2x)-13
- 16+6x=5(1+2x)-13
- 2*sinx^2*πx/16+6*x+9=0
- 16+6*x=64
16+6x=5(1-2x)-13 equation
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The solution
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[src]
16 + 6*x = 5*(1 - 2*x) - 13
$$6 x + 16 = 5 \cdot \left(- 2 x + 1\right) - 13$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$6 x = - 10 x - 24$$
Move the summands with the unknown x
from the right part to the left part:
$$16 x = -24$$
Divide both parts of the equation by 16
We get the answer: x = -3/2
16+6*x = 5*(1-2*x)-13
Expand brackets in the right part
16+6*x = 5*1-5*2*x-13
Looking for similar summands in the right part:
16 + 6*x = -8 - 10*x
Move free summands (without x)
from left part to right part, we given:
$$6 x = - 10 x - 24$$
Move the summands with the unknown x
from the right part to the left part:
$$16 x = -24$$
Divide both parts of the equation by 16
x = -24 / (16)
We get the answer: x = -3/2
Sum and product of roots
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sum
-3/2
$$\left(- \frac{3}{2}\right)$$
=
-3/2
$$- \frac{3}{2}$$
product
-3/2
$$\left(- \frac{3}{2}\right)$$
=
-3/2
$$- \frac{3}{2}$$
The graph