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(Abs(2*log(0.)*5*(x)-3))=-log(0.)*5*(x) equation

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|2*log(0)*5*x - 3| = -log(0)*5*x
$$\left|{x 5 \cdot 2 \log{\left(0 \right)} - 3}\right| = x 5 \left(- \log{\left(0 \right)}\right)$$
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