Mister Exam
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How to use it?
- Equation:
- Equation x-y=1
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Equation 4-6*(x+2)=3-5*x
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Equation 4-6(x+2)=3-5x
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Equation 1/(x-3)^2-3/(x-3)-4=0
- Express {x} in terms of y where:
- 18*x-8*y=-2
- -11*x+15*y=7
- 6*x+17*y=3
- 4*x+2*y=5
- Derivative of:
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3-5x
- Graphing y =:
- 3-5x
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Identical expressions
- four - six (x+ two)= three -5x
- 4 minus 6(x plus 2) equally 3 minus 5x
- four minus six (x plus two) equally three minus 5x
- 4-6x+2=3-5x
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Similar expressions
- x^3-5*x^2-4*x+20=0
- 4-6(x+2)=3+5x
- 4-6*(x+2)=3-5*x
- 3*x^2*y^3-5*x^3*y^2=4
- 4+6(x+2)=3-5x
- 4-6*(x+2)=3-5x
- 4-6(x-2)=3-5x
- 4-(6x+2)=2x
- 3-5(x+1)=6-4x
4-6(x+2)=3-5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 11 - 5 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 11$$
Divide both parts of the equation by -1
We get the answer: x = -11
4-6*(x+2) = 3-5*x
Expand brackets in the left part
4-6*x-6*2 = 3-5*x
Looking for similar summands in the left part:
-8 - 6*x = 3-5*x
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 11 - 5 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 11$$
Divide both parts of the equation by -1
x = 11 / (-1)
We get the answer: x = -11
The graph