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log(0.)*5*(x-3)+1=log(0.)*5*(3*x-7)-log(0.)*5*(x+3) equation

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The solution

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log(0)*5*(x - 3) + 1 = log(0)*5*(3*x - 7) - log(0)*5*(x + 3)
$$5 \log{\left(0 \right)} \left(x - 3\right) + 1 = - 5 \log{\left(0 \right)} \left(x + 3\right) + 5 \log{\left(0 \right)} \left(3 x - 7\right)$$
Sum and product of roots [src]
sum
0
$$0$$
=
0
$$0$$
product
1
$$1$$
=
1
$$1$$
1