Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation 3*x^2-48=0
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Equation x^3+4*x^2-9*x-36=0
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Equation x^4=1
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Equation 4(x-1)=2(2x-8)+12
- Express {x} in terms of y where:
- 4*x+13*y=8
- 14*x+17*y=19
- 3*x-11*y=20
- -18*x-13*y=2
- How do you in partial fractions?:
- (x^2-9)/(x+3)
- Derivative of:
- (x^2-9)/(x+3)
- Integral of d{x}:
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(x^2-9)/(x+3)
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Identical expressions
- (x^ two - nine)/(x+ three)= zero
- (x squared minus 9) divide by (x plus 3) equally 0
- (x to the power of two minus nine) divide by (x plus three) equally zero
- (x2-9)/(x+3)=0
- x2-9/x+3=0
- (x²-9)/(x+3)=0
- (x to the power of 2-9)/(x+3)=0
- x^2-9/x+3=0
- (x^2-9)/(x+3)=O
- (x^2-9) divide by (x+3)=0
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Similar expressions
- (x^2+9)/(x+3)=0
- (x^2-9)/(x-3)=0
(x^2-9)/(x+3)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 9}{x + 3} = 0$$
transform:
$$\frac{\left(x - 3\right) \left(x + 3\right)}{x + 3} = 0$$
$$x - 3 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = 3$$
We get the answer: x = 3
$$\frac{x^{2} - 9}{x + 3} = 0$$
transform:
$$\frac{\left(x - 3\right) \left(x + 3\right)}{x + 3} = 0$$
$$x - 3 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = 3$$
We get the answer: x = 3
The graph