(x^2-9)/(x+3)=0 equation
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The solution
Detail solution
Given the equation:
$$\frac{x^{2} - 9}{x + 3} = 0$$
transform:
$$\frac{\left(x - 3\right) \left(x + 3\right)}{x + 3} = 0$$
$$x - 3 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = 3$$
We get the answer: x = 3
Sum and product of roots
[src]
$$3$$
$$3$$
$$3$$
$$3$$