This equation is of the form a∗x2+b∗x+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=1 b=−5 c=9 , then D=b2−4∗a∗c= (−1)1⋅4⋅9+(−5)2=−11 Because D<0, then the equation has no real roots, but complex roots is exists. x1=2a(−b+D) x2=2a(−b−D) or x1=25+211i Simplify x2=25−211i Simplify
Vieta's Theorem
it is reduced quadratic equation px+x2+q=0 where p=ab p=−5 q=ac q=9 Vieta Formulas x1+x2=−p x1x2=q x1+x2=5 x1x2=9