Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
-
Equation x^2+6=5x
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 16*x+14*y=-14
-
Identical expressions
- (x+ three)/ four =(2x- seven)/ five
- (x plus 3) divide by 4 equally (2x minus 7) divide by 5
- (x plus three) divide by four equally (2x minus seven) divide by five
- x+3/4=2x-7/5
- (x+3) divide by 4=(2x-7) divide by 5
-
Similar expressions
- ((8*x-5)/3)-((4*x+3)/4)+((2-9*x)/2)=0
- (2/3x+3/4)*(2/3x+3/4)-14.75=(1/3x-2)*((1+1/3)x+8)
- x+3/4=3x-2/8
- (2x-7)/(5)=4
- (x+3)/4=(2x+7)/5
- x+3/4=2x-7/5
- (x-3)/4=(2x-7)/5
- x+3/4-x/2=3
(x+3)/4=(2x-7)/5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{4} = \frac{2 x}{5} - \frac{43}{20}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-3\right) x}{20} = - \frac{43}{20}$$
Divide both parts of the equation by -3/20
We get the answer: x = 43/3
(x+3)/4 = (2*x-7)/5
Expand brackets in the left part
x/4+3/4 = (2*x-7)/5
Expand brackets in the right part
x/4+3/4 = 2*x/5-7/5
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{4} = \frac{2 x}{5} - \frac{43}{20}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-3\right) x}{20} = - \frac{43}{20}$$
Divide both parts of the equation by -3/20
x = -43/20 / (-3/20)
We get the answer: x = 43/3
Sum and product of roots
[src]
sum
43/3
$$\frac{43}{3}$$
=
43/3
$$\frac{43}{3}$$
product
43/3
$$\frac{43}{3}$$
=
43/3
$$\frac{43}{3}$$
43/3